xx+2xy-10x=0 y.y+2xy-10y=0
xx+2xy-10x=0 y.y+2xy-10y=0
已知x,y是实数,且适合方程(xx+xy-12)(xx+xy-12)+(xy-2yy-1)(xy-2yy-1)=0求x,
已知xx+y=5,xy=-3,则x^2y+xy^2=
7.X*X+2X+Y*Y-6Y+10=0,则xy=?
x^2-2xy+y^2+6y+10=0求x,y的值.
x的平方-2xy+y的平方-6y+10=0,求x,y
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-
xy+ 2=0,x+y-3=0求(3xy+10y))+[5x-(2xy+2y-3x)]
若(3xy+2)+|7-x-y|=0,求代数式(5xy+10y)-[-5x-(4xy-2y+3x)]的值.
若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
已知y-x-2xy=0,求3x+xy-3y/y-xy-x的值
已知y-x-2xy=0,求(3x+xy-3y)\(y-xy-x)的值