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为什么函数可以展为麦克劳林级数

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为什么函数可以展为麦克劳林级数
RT
The basic idea is that the polynomial functions P = {x^n,n= 0,1,2,...} are linearly independent,so P should expand to an (infinite-dimensional) subspace.Maclaurin series of a function F can be seen as a "projection" of F onto that subspace P.