如图,已知AB=AC,AD=AE,BE=CD,
如图,已知AB垂直AC,AD垂直AE,AB=AC,AD=AE,求证BE=CD且BE垂直CD.图在后面.
如图,已知AB=AC,AD=AE,BE=CD,
如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD
已知:如图,AB=AC,AD=AE,BE、CD交于点G.求证:AG平分角BAC
已知:如图,CD,BE是三角形ABC的高.求证:(1).AD:AC=AE:AB (2).角AED
已知如图,AB=AC,∠1=∠2,AD⊥CD,AE⊥BE,求证:AD=AE
如图,已知AE⊥AD,AF⊥AB,AB//CD,AE=CD,AE=AD,AF=CD,求证AC=EF
已知,如图,AB=AC,D,E分别是AB,AC上的点,AD=AE,BE与CD相交于点G
已知,如图,AB=AC,点D,E分别在AB,AC上,且AD=AE,BE,CD相交于O,
已知:如图,AB=AC,BE⊥AC ,CD⊥AB,垂足分别为E,D.求证:AD=AE
ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
如图,在梯形ABCD中,已知AD∥BC,AB=CD,延长线段CB到E,使BE=AD,连接AE、AC.