计算：(1/9a^2+6a+1-1/3a+1)/a^2/3a^2+a

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/09 08:04:26

=(1/(3a+1)^2-1/(3a+1))/(a^2/3a^2+a)
=(3a/(3a+1)^2)/(a^2/3a^2+a)
=(3a/(3a+1)^2)/(a/(3a+1))
=3/(3a+1)

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