作业帮已知x=2008,y=2006,求x-x÷{x^2-y^2/x^3+y^3[(x-x^2+y^2/y)÷(1/x-1/y
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已知x=2008,y=2006,求x-x÷{x^2-y^2/x^3+y^3[(x-x^2+y^2/y)÷(1/x-1/y)]}的值
x-x÷{x^2-y^2/x^3+y^3[(x-x^2+y^2/y)÷(1/x-1/y)]}
=x-x÷{(x+y)(x-y)/(x+y)(x^2-xy+y^2)[((xy-x^2+y^2)/y)÷(y-x/xy)]}
=x-x÷{(x-y)/(x^2-xy+y^2)[((x^2-xy+y^2)/y)*(xy/(x-y))]}
=x-x÷{(x-y)/(x^2-xy+y^2)*x(x^2-xy+y^2)/(x-y)}
=x-x÷x
=x-1
=2008-1
=2007
=x-x÷{(x+y)(x-y)/(x+y)(x^2-xy+y^2)[((xy-x^2+y^2)/y)÷(y-x/xy)]}
=x-x÷{(x-y)/(x^2-xy+y^2)[((x^2-xy+y^2)/y)*(xy/(x-y))]}
=x-x÷{(x-y)/(x^2-xy+y^2)*x(x^2-xy+y^2)/(x-y)}
=x-x÷x
=x-1
=2008-1
=2007
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