>>> a,b=0,1 >>> while b>> a,b=0,1
>>> a,b=0,1 >>> while b>> a,b=0,1
while( ('\0' = *a) && ('\0' = *b) )
.main() { int a=1,b=10; do {b-=a;a++;}while(b--
main() { int a=18,b=11; while (a!=b) {while(a>b) a-=b;while(
b的值为( ).a=1; b=10; do { b-=a; a++; } while (b--
# include main() { int a=-2,b=0; while(a++&&++b); printf("%d
分析下面的 C 语言代码:int a=1,b=10; do{ b-=a; a++; }while (b- -
while(scanf("%d%d",&a,&b)!=EOF,a||b)
分析下面的C语言代码:inta=1,b=10;do{b-=a;a++;}while(b--<0);则执行循环语句后
{1,a,b/a}={0,a^2,a+b}
已知2a-b+1的绝对值+(3a+3/2b)^=0,求(b^/a+b)÷{[(b/a-b)+1][a-(a^/a+b)]
设a,b∈R,集合{1,a+b,a}={0,b/a,b},则b-a=?