设y=√(x^2-1)求dy/dx

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/10/02 19:15:28

设y=√(x^2-1)求dy/dx

这是最简单的复合函数
y=√u
u=x²-1
dy/dx=dy/du*du/dx
=(1/2√u)*2x
=x/2√x²-1

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