main() { int n1,n2=1298; while(n2!=0) { n1=n2%10;n2=n2/10;pr
main() { int n1,n2=1298; while(n2!=0) { n1=n2%10;n2=n2/10;pr
main(){int n1,n2=1234; while(n2!=0){n1=n2%10;n2=n2/10;}print
int n1=n2=10;对吗?
n1=2,n2=++n1,n1=n2++ 执行后n1,n2的值
v1:v2=n1:n2由来
比如v1:v2=n1:n2这些
推论:P1/P2=n1/n2
若自然数n1>n2,且n1^2-n2^2-2n1-2n2=19,求n1与n2的值
变压器u1/u2=n1/n2,电路互感器I1/I2=n2/n1的推导过程
已知a(n1+n2)=a(n1)*a(n2)求证为等比数列
设有定义:int n1=0,n2,*p=&n2,*q=&n1;,以下赋值语句中与n2=n1;语句等价的是( )A*p=*
设有定义:int n1=0,n2,*p=&n2,*q=&n1; 以下赋值语句中与n2=n1:语句等价的是 A.*p=*q