In a horse race,the odds in favor of the first horse winning
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In a horse race,the odds in favor of the first horse winning is an 8-horse race are 2 to 5 .The odds against the second horse winning are 7 to 3.What is the probability that one of these horses will win?
赛马中,八匹马比赛里第一匹马的赢率是2比5,第二匹马的赔率是7比3.两匹马中任一匹赢的概率是多少?
赢率 = 赢的机会:输的机会,概率 = 赢的机会/ (赢的机会 + 输的机会)
赔率 = 输的机会:赢的机会,概率 =赢的机会/ (赢的机会 + 输的机会)
所以第一匹马赢的概率是 2/(2+5)= 2/7,第二匹马赢的概率是3/(7+3)= 3/10
任一匹马赢的概率是 2/7 + 3/10 = 41/70
赢率 = 赢的机会:输的机会,概率 = 赢的机会/ (赢的机会 + 输的机会)
赔率 = 输的机会:赢的机会,概率 =赢的机会/ (赢的机会 + 输的机会)
所以第一匹马赢的概率是 2/(2+5)= 2/7,第二匹马赢的概率是3/(7+3)= 3/10
任一匹马赢的概率是 2/7 + 3/10 = 41/70
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