作业帮1. 3x2+5xy--2y2+x+9y--4
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/07/09 08:11:50
1. 3x2+5xy--2y2+x+9y--4
2. (x2+x+1)(x2+x+2)--12
3. (a+b--2ab)(a+b--2)+(1--ab)2
2. (x2+x+1)(x2+x+2)--12
3. (a+b--2ab)(a+b--2)+(1--ab)2
1.3x²+5xy--2y²+x+9y--4
=(3x-y)(x+2y)-(3x-y)+4x+8y-4
=(3x-y)(x+2y-1)+4(x+2y-1)
=(3x-y+4)(x+2y-1)
2.(x²+x+1)(x²+x+2)--12
=(x²+x)²+3(x²+x)+2-12
=(x²+x)²+3(x²+x)-10
=(x²+x+5)(x²+x-2)
=(x²+x+5)(x+2)(x-1)
3.(a+b--2ab)(a+b--2)+(1--ab)²
=(a+b)²-(2+2ab)(a+b)+4ab+1-2ab+a²b²
=(a+b)²-(2+2ab)(a+b)+1+2ab+a²b²
=(a+b)²-(2+2ab)(a+b)+(1+ab)²
=[(1+ab)-(a+b)]²
=(ab-a-b+1)²
=[a(b-1)-(b-1)]²
=(a-1)²(b-1)²
=(3x-y)(x+2y)-(3x-y)+4x+8y-4
=(3x-y)(x+2y-1)+4(x+2y-1)
=(3x-y+4)(x+2y-1)
2.(x²+x+1)(x²+x+2)--12
=(x²+x)²+3(x²+x)+2-12
=(x²+x)²+3(x²+x)-10
=(x²+x+5)(x²+x-2)
=(x²+x+5)(x+2)(x-1)
3.(a+b--2ab)(a+b--2)+(1--ab)²
=(a+b)²-(2+2ab)(a+b)+4ab+1-2ab+a²b²
=(a+b)²-(2+2ab)(a+b)+1+2ab+a²b²
=(a+b)²-(2+2ab)(a+b)+(1+ab)²
=[(1+ab)-(a+b)]²
=(ab-a-b+1)²
=[a(b-1)-(b-1)]²
=(a-1)²(b-1)²
1. 3x2+5xy--2y2+x+9y--4
2x2+xy-3y2+x+4y-1因式分解
已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是
已知2x-3*根号(xy)-2y=0(x>0),则x2+4xy-16y2除以2x2+xy-9y2的值是多少?
已知2x=3y,求xy／(x2+y2)-y2／(x2-y2)的值
分解因式：x2+3xy+2y2+4x+5y+3．
2x2+xy-y2-5x+4y-3如何因式分解?
x2－(a＋b)xy+aby2 x2+4xy－5y2 x2－5x+3 2x2+xy－y2－4x+5y－6
已知x+y=4，xy=2，则x2+y2+3xy=______．
已知x+y=4，xy=2，求x2+y2+3xy的值．
x2-2xy+y2+3x-3y+2．
x2-xy-2y2-x+5y-2