27^2*9^4=3^k,k=

求证：lim1^k+2^k+3^k+4^k+.n^k/n^(k+1)=1/k+1 27^2*9^4=3^k,k= k^4+2k^2-6k-3=0 K-1+K+2+K/3+K*3=2001 请问1^k+2^k+3^k+.+n^k=? 3×k×k-2k-1=-1.k等于 2k/3h-2k=3k/4k-6h 4k^3+6k^2+k+1=0.求K~ (9/4)^2+(K/4)^2=(3-K/4)^2求K的值 c语言 求1^k+2^k+3^k+……+n^k,假定n=6,k=4 若x的3k次方=27,y的2k次方=9,则x的6k次方×y的4k次方 当k等于?时,3k(2k-5)+2k(1-3k)=52