麻烦各位了.数学题(1)12a³b²-9a²+3ab(2)121x²-144y&
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/11/08 11:13:49
麻烦各位了.数学题
(1)12a³b²-9a²+3ab
(2)121x²-144y²
(3)4(a-b)²-(x-y)²
(4)(x-2)²+10(x-2)+25
(5)(a²-2ab+b)²-4
(6)16x²-4y²
(7)m²(x-y)+n²(y-x)
(8)(x²+y²)²-4x²y²
(9)(x²+2x)²+2(x²+2x)+1
(10)(xy+1)(x+1)(-y+1)+xy
(11) 2x²+2x+2/1
(12)(a-b)(3a+b)²+(a+3b)²(b-a)4x²-9y²=31的正整数解
谢谢了,要过程= =
化简
(1)12a³b²-9a²+3ab
(2)121x²-144y²
(3)4(a-b)²-(x-y)²
(4)(x-2)²+10(x-2)+25
(5)(a²-2ab+b)²-4
(6)16x²-4y²
(7)m²(x-y)+n²(y-x)
(8)(x²+y²)²-4x²y²
(9)(x²+2x)²+2(x²+2x)+1
(10)(xy+1)(x+1)(-y+1)+xy
(11) 2x²+2x+2/1
(12)(a-b)(3a+b)²+(a+3b)²(b-a)4x²-9y²=31的正整数解
谢谢了,要过程= =
化简
这干什么的,化简?
(1)12a³b²-9a²+3ab =
(2)121x²-144y² =(11x+12y)(11x-12y)
(3)4(a-b)²-(x-y)²=(2a-2b+x-y)(2a-2b-x+y)
4)(x-2)²+10(x-2)+25 =(x-2+5)²=(x+3)²
(5)(a²-2ab+b)²-4=(a²-2ab+b+2)(a²-2ab+b-2)
(6)16x²-4y²=(4x+2y)(4x-2y)
(7)m²(x-y)+n²(y-x)=(x-y)(m²-n²)
(8)(x²+y²)²-4x²y²=( x²+y²+2xy)(x²+y²-2xy)=(x+y)²(x-y)²
(9)(x²+2x)²+2(x²+2x)+1= (x²+2x+1)²=(x+1)²
(10)(xy+1)(x+1)(-y+1)+xy =
(11) 2x²+2x+2/1 =2(x²+x+1/4)=2(x+1/2)²
(12)(a-b)(3a+b)²+(a+3b)²(b-a)4x²-9y²=31的正整数解
(1)12a³b²-9a²+3ab =
(2)121x²-144y² =(11x+12y)(11x-12y)
(3)4(a-b)²-(x-y)²=(2a-2b+x-y)(2a-2b-x+y)
4)(x-2)²+10(x-2)+25 =(x-2+5)²=(x+3)²
(5)(a²-2ab+b)²-4=(a²-2ab+b+2)(a²-2ab+b-2)
(6)16x²-4y²=(4x+2y)(4x-2y)
(7)m²(x-y)+n²(y-x)=(x-y)(m²-n²)
(8)(x²+y²)²-4x²y²=( x²+y²+2xy)(x²+y²-2xy)=(x+y)²(x-y)²
(9)(x²+2x)²+2(x²+2x)+1= (x²+2x+1)²=(x+1)²
(10)(xy+1)(x+1)(-y+1)+xy =
(11) 2x²+2x+2/1 =2(x²+x+1/4)=2(x+1/2)²
(12)(a-b)(3a+b)²+(a+3b)²(b-a)4x²-9y²=31的正整数解
麻烦各位了.数学题(1)12a³b²-9a²+3ab(2)121x²-144y&
3a-3b/10ab*25a²b³/a²-b² x²-4y²
因式分解和整式乘除1)2X×12x³2)(a+b)-13)121x²-9y²2²
计算:1】—(2ab)³+3ab x a²b²2】(—2x³)² x
单项式除以单项式2a²(x-y)³+3a²(y-x)²
帮我化简2道数学题①2a(a-b)³-a²(a-b)²②7y(x-3y)²-2(
(X+y)²-(x+y)³和4ab(a+b)²-6a²b(a+b).用提取公因式
3x³+2x-5,4x²-4x-1,a³-3a²b+3ab²-b&su
1.计算(-a²b²)÷(-ab²)×(-3ab³)2.先化简再求值「(x-y)
1.分解因式:(1)16a-b²/9(9分之b²)(2)3ab³-3a³b2.利
2(a²b+3ab²)-3(a²b-1)-2a²b-2
各位大虾们,1)(2a²)³•2²•a-(3a³) &s