设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)值为
三角函数:设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)的值为多少?
设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)的值为多少?
设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)值为
设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)的值为?
设a为锐角,若cos(a+π/6)=3/5,则sin(a-π/12)=
设A为锐角 若cos(A+π/6)=0.8,则sin(2A+π/12)=?
设a为锐角,若cos(a+π/6)=3/5,则sin(a–π/12)的值为?
a为锐角 cos(a+π/6)=4/5 求sin(2a+π/12)
、设a为锐角,若cos(a+pi/6)=4/5,则sin(2a+pi/12)的值为?
设a为锐角,若cos(a+pi/6)=4/5,则sin(2a+pi/12)的值为?
若a为锐角,cos(a+30)=4/5,则sin(2a+15)=
设a为锐角,若cos(a+6分之拍)=5分之3,则sin(a-12分之拍)=?