int x=17,y=26; printf ("%d",y/=(x%=6));解释一下
int x=17,y=26; printf ("%d",y/=(x%=6));解释一下
main() { int x=10; int y=x++; printf("%d,%d\n",(x++,y),y++);
int x=3,y=4; printf("%d,%d",(x.y),(y,x));
int x,y; x=13; y=5; {printf("%d",x%=(y/=2));
#include main() { int x=1,y=3; x=9-(--y)-(--y); printf("%d",
void fun(int x,int y) {x=x+y;y=x-y;x=x-y; printf("%d,%d,",x,
int x=10,y=20; main() {func();printf("%d,%d\n",x,y);} func()
int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么
int x=12,y=8; printf("%d\t%d\t%d\n",x,x&y,x|y);
int main( ) { int x,y,d; d=3.2; x=1.2; y=(x+3.8)/5.0; printf
c语言:main()?{int x,y,z;?x=y=1;?z=x++,y++,++y;?printf("%d,%d,%
int x=10,y; y=(x++)+(--x); printf("%d,%d",x,y); C语言运行结果 是10,