(2012•广陵区二模)先化简再求值:(3x−1−x−1)÷x−2x
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(2012•广陵区二模)先化简再求值:(
−x−1)÷
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x−1 |
x−2 |
x
原式=[
3 x−1- (x−1)(x+1) x−1]• (x−1)2 x−2 =- x2−4 x−1• (x−1)2 x−2 =- (x+2)(x−2) x−1• (x−1)2 x−2 =-(x+2)(x-1) =-x2-x+2, 解x2-2x=0得:x1=0,x2=2(使分式无意义,舍去), ∴当x=0时,原式=-0-0+2=2.
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