数列an中若an+1=1/2an+2,且a1=1求an
数列an中若an+1=1/2an+2,且a1=1求an
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列{an}中,a1=35,an+1-an=2n-1,求an
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
数列an中,a1=3,an+1=an/2an+1,则an=?
已知数列{an}中a1=3且an+1=an+2n.求数列的通项公式
在数列an中,a1=2,an+1=an/an+3,求an 麻烦讲得详细点
已知数列{an中}a1=3.且an+1=an+2的n次方
数列an中已知a1=3,且2an=SnSn-1,求通项公式an
已知数列{an}中a1=6,且an-an-1=(an-1/n)+n+1(n属于N*,n≥2),求an
数列an中 a1=1 a(n+1)=2an\(an+2) 求数列通项公式an
已知数列an中 a1=-2且an+1=sn(n+1为下标),求an,sn