利用简便算法,并探索规律:
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/11/09 10:47:01
利用简便算法,并探索规律:
(1)99×99+199 (2)999×999+1999
(3)99…9(100个9)×99…9(100个9)+199…9(100个9)
(4)99…9(2500个9)×99…9(2500个9)+199…9(2500个9)
(5)一般地,99…9(N个9)×99…9(N个9)+199…9(N个9)
(1)99×99+199 (2)999×999+1999
(3)99…9(100个9)×99…9(100个9)+199…9(100个9)
(4)99…9(2500个9)×99…9(2500个9)+199…9(2500个9)
(5)一般地,99…9(N个9)×99…9(N个9)+199…9(N个9)
(1)99×99+199
=99*99+99+100
=99*(99+1)+100
=99*100+100
=9900+100
=10000
(2)999×999+1999
=999*999+999+1000
=999*(999+1)+1000
=999*1000+1000
=999000+1000
=1000000
(3)99…9(100个9)×99…9(100个9)+199…9(100个9)
=99…9(100个9)*99…9(100个9)+99…9(100个9) +100...0(100个0)
=99…9(100个9)*(99…9(100个9)+1)+100...0(100个0)
=99…9(100个9)*100...0(100个0)+100...0(100个0)
=100...0(200个0)
(4)99…9(2500个9)×99…9(2500个9)+199…9(2500个9)
=99...(2500个9)*99...9(2500个9)+99...9(2500个)+100...0(2500个)
=99...9(2500个9)*(99...9(2500个9)+1)+100...0(2500个0)
=100...0(5000个0)
(5)一般地,99…9(N个9)×99…9(N个9)+199…9(N个9)
=99...9(N个9)*99...9(N个9)+99...9(N个9)+100...0(N个0)
=99...9*(99...9(N个9)+1)+100...0(N个0)
=100...0(2N个0)
=99*99+99+100
=99*(99+1)+100
=99*100+100
=9900+100
=10000
(2)999×999+1999
=999*999+999+1000
=999*(999+1)+1000
=999*1000+1000
=999000+1000
=1000000
(3)99…9(100个9)×99…9(100个9)+199…9(100个9)
=99…9(100个9)*99…9(100个9)+99…9(100个9) +100...0(100个0)
=99…9(100个9)*(99…9(100个9)+1)+100...0(100个0)
=99…9(100个9)*100...0(100个0)+100...0(100个0)
=100...0(200个0)
(4)99…9(2500个9)×99…9(2500个9)+199…9(2500个9)
=99...(2500个9)*99...9(2500个9)+99...9(2500个)+100...0(2500个)
=99...9(2500个9)*(99...9(2500个9)+1)+100...0(2500个0)
=100...0(5000个0)
(5)一般地,99…9(N个9)×99…9(N个9)+199…9(N个9)
=99...9(N个9)*99...9(N个9)+99...9(N个9)+100...0(N个0)
=99...9*(99...9(N个9)+1)+100...0(N个0)
=100...0(2N个0)