作业帮
X²-6x+9 x²-9 x+3
x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x)
已知(x²-3x+1)／x＝1,求(x⁴-9x²+1)／x²的值
(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)
不等式|(x+3)/x|>(x+3)/x,不等式（x²-9）/(x-2)＞0
x²+9x/x²+3x+x²-9/x²+6x=9
x²+9x/x²+3x + x²-9/x²+6x+9=
1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x
(1-x/3-x)²/(3-2x-x²/9-x²)³*(x²/x
分式计算x²+2x／x²-6x+9÷x²-4／x²-3x
x²＋2x/x²-6x+9÷x²-4/x²-3x ,
分式计算：x²+2x／x²-6x+9÷x²-4／x²-3x