来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/02 18:14:46
戴维南定理求电流
![](http://img.wesiedu.com/upload/f/6b/f6b0326f2f394224cb4857d2e3b0a4a9.jpg)
断开 R5 两端,左、右是两个闭合回路,求出E1、E2 的等效参数:
E1' = E1 * R2 / (R1+R2) = 45 * 20 / 25 = 36V
R1' = R1 // R2 = 5 * 20 / 25 = 4Ω
E2' = E2 * R3 / (R3+R4) = 44.8V
R4' = R3 // R4 = 2.8Ω
![](http://img.wesiedu.com/upload/f/86/f86afc6d2e9f2ba6080f1064112e5afd.jpg)
I = (E2' - E1')/ (R1'+R5+R4')
= 8.8 / 8.8
= 1A