请问怎么证明sinX+sin(X+Y)+sin(X+2Y)/cosX+cos(X+Y)+cos(X+2Y)=tan(X+
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/03 08:02:13
请问怎么证明sinX+sin(X+Y)+sin(X+2Y)/cosX+cos(X+Y)+cos(X+2Y)=tan(X+Y),
sinX+sin(X+Y)+sin(X+2Y)/cosX+cos(X+Y)+cos(X+2Y)
=sinX+sin(X+2Y)+sin(X+Y)/cosX+cos(X+2Y)+cos(X+Y)
=2sin(X+X+2Y)/2cos(X-X-2Y)/2+sin(X+Y)/2cos(X+X+2Y)/2cos(X-X-2Y)/2+cos(X+Y)
=2sin(X+Y)cosY+sin(X+Y)/2cos(X+Y)cosY+cos(X+Y)
=sin(X+Y)(2cosY+1)/cos(X+Y)(2cosY+1)
=sin(X+Y)/cos(X+Y)
=tan(X+Y)
再问: 看起来有点复杂,请问能变得简单点吗?
再答: 这是必须的步骤,没法再简单点了
=sinX+sin(X+2Y)+sin(X+Y)/cosX+cos(X+2Y)+cos(X+Y)
=2sin(X+X+2Y)/2cos(X-X-2Y)/2+sin(X+Y)/2cos(X+X+2Y)/2cos(X-X-2Y)/2+cos(X+Y)
=2sin(X+Y)cosY+sin(X+Y)/2cos(X+Y)cosY+cos(X+Y)
=sin(X+Y)(2cosY+1)/cos(X+Y)(2cosY+1)
=sin(X+Y)/cos(X+Y)
=tan(X+Y)
再问: 看起来有点复杂,请问能变得简单点吗?
再答: 这是必须的步骤,没法再简单点了
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