为什么|x|+|y|=根号[(x+y)^2-2xy+2|xy|]
为什么|x|+|y|=根号[(x+y)^2-2xy+2|xy|]
x根号x+x根号y/xy-y^2)-(x+根号xy+y/x根号x-y根号)y
{(x-y)/(根号x+根号y)}-(x+y-2倍根号xy)/(根号x-根号y)=?
已知正实数x y满足x-根号xy-2y=0求 x+3根号xy+2y/2x-2根号下xy-y
已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值
已知:x>0,y>0,x-2y=根号xy.求(x+(根号xy)+y)/(x-(根号xy)-y)
(x+y)/(根号下x+根号下y)+2xy/(x根号下y+y根号下x)=______.
(xy-x^2)乘以(xy)/(x-y)
已知x>0,y>0,x+根号xy-6y=0,求4x+5根号xy-6y分之x+2根号xy
已知根号x(根号x-根号y)=根号xy+3y,求(3x-y)分之2x+3倍根号xy-y 的值
①{(x+y)/(根号x+根号y)}+{2xy/根号xy(根号x+根号y)}
【(x-y)^3(x^1/2+y^1/2)^-3+3(x根号y-y根号x)】/(x根号x+y根号y)+(2xy根号xy-