设a>b>1,log(a)b+log(b)a=10/3,则log(a)b-log(b)a=

设a>b>1,log(a)b+log(b)a=10/3,则log(a)b-log(b)a= log a b*log b c=log b b*log a c成立吗 log a b=log b a,则：ab=? 设a>b>1,且loga(b)+log(b)a=10/3,求loga(b)-log(b)a 已知a大于b大于1,log(a)b+log(b)a=10/3,求log(a)b-log(b)a的值 已知a＜b＜1,log(a)b+log(b)a=10/3,求log(a)b-log(b)a的值 log(ab)=log(a)+ log(b)吗 a^[log(a)b×log(b)c×log(c)N] 公式：log(a)(b)*log(b)(a)=? 利用换底公式证明：log(a)b.log(b)c.log(c)a=1 设log(2)(3)=a,log(3)(7)=b,以a,b表示log(21)(56) 化简log(1/a)b+log(a)b