作业帮y=(x-3)/(x-2) yx-2y=x-3 (y-1)x=2y-3 x=(2y-3)/(y-1) ∴y≠1
y=(x-3)/(x-2) yx-2y=x-3 (y-1)x=2y-3 x=(2y-3)/(y-1) ∴y≠1
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
2(x+y) 3x+3y=24 x+y/2x x y/2y= 1
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
已知x-3y=0，求2x+yx
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
已知：3x=8y.求（1）x+y/y (2)2x+3y/x-2y