化简sin(θ-5π)•cot(π2-θ)•cos(8π-θ)tan(3π-θ)•tan(θ-32π)•sin(-θ-4

化简sin(θ-5π)•cot(π2-θ)•cos(8π-θ)tan(3π-θ)•tan(θ-32π)•sin(-θ-4 sin(θ -5π)/tan(3π-θ)*cot(π/2-θ)/tan(θ -3/2π)*cos(8π-θ)/sin(- 化简[cot(θ+4π)cos(θ+π)sin²(θ+3π)]/[tan(π+θ)cos²(-π-θ 化简:cos^2θcotθ+sin^2θtanθ+2cosθsinθ [cot（θ+4π）·cos（θ+π）·sin^2（θ+3π）]/[tan（π+θ）·cos^3（-π-θ）] 已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值 已知【2+tan(θ-π)】/【1-tan(2π-θ】=-4,求(sinθ-3cosθ)(cosθ-sinθ)的值 有道数学题帮下忙cot(sinθ)*tan(cosθ) 已知tan(θ+π/4)=-2,求cosθ平方+sinθcosθ-1 化简：cot(θ+4π)•cos(θ+π)•sin 求证(tan(2π-θ)sin(2π-θ)cos(6π-θ))/((-cosθ)sin(5π+θ))=tanθ 已知tanθ+cotθ=2,求sin^3θ-cos^3θ的值