C(0,0)+1/2C(1,n)+1/3C(2,n)+…1/kC(k-1,n)…+1/(n+1)C(n,n)=1/(n+
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/10/06 13:53:38
C(0,0)+1/2C(1,n)+1/3C(2,n)+…1/kC(k-1,n)…+1/(n+1)C(n,n)=1/(n+1)
证明:1/iC(i-1,n)=1/i*n!/(i-1)!*(n+1-i)!)=n!/(i!*(n-1+i)!)
=1/(n+1)(n+1)!/(i!*(n+1-i)!)=1/(n+1)C(i,n+1)
C(0,0)+1/2C(1,n)+1/3C(2,n)+…1/kC(k-1,n)…+1/(n+1)C(n,n)
=1/(n+1)(C(0,n+1)+C(1,n+1).+C(n,n+1))
=(2^(n+1)-1)/(n+1)
题目出错了,具体做法请见上面,
祝好~
=1/(n+1)(n+1)!/(i!*(n+1-i)!)=1/(n+1)C(i,n+1)
C(0,0)+1/2C(1,n)+1/3C(2,n)+…1/kC(k-1,n)…+1/(n+1)C(n,n)
=1/(n+1)(C(0,n+1)+C(1,n+1).+C(n,n+1))
=(2^(n+1)-1)/(n+1)
题目出错了,具体做法请见上面,
祝好~
C(0,0)+1/2C(1,n)+1/3C(2,n)+…1/kC(k-1,n)…+1/(n+1)C(n,n)=1/(n+
组合:C(n,0)+C(n,1)+……+C(n,n)=n^2
证明:C(0,n)+1/2C(1,n)+1/3C(2,n)+……+1/kC(k-1,n)+……+1/(n+1)C(n,n
证明C(0,n)^2+C(1,n)^2+……+C(n,n)^2=C(n,2n)
C(n.0)+2C(n.1)+4C(n.2)+C(n.2)+C(n.3)…+C(n.n)=?
计算:C(1,n)+2C(2,n)+3C(3,n) + … + nC(n,n)
求证:C(0,n)+2C(1,n)+.+(n+1)C(n,n)=2^n+2^(n-1)
(1+2)^n = C(n,0) +2C(n,1) +2^2C(n,2) +2^3C(n,3)+……+2^nC(n,n)
急1)C(n,0)+2C(n,1)+3C(n,2)+4C(n,3) +...+(n+1)C(n,n)=(n+2)*2^(
C(0,n)+2C(1,n)+3C(2,n)+...+(r+1)C(r,n)+...+(n+1)C(n,n)=___(n
排列组合 C(0 n)+C(1 n)+C(2 n)+...+C(n-1 n)+C(n n)(n∈N*)的值,并证明你的结
组合猜想C(0,n)+C(1,n)+C(2,n)+C(3,n)+.+C(n,n) n∈N*的值,并证明你的结论