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英语高手大侠们,能再给小馒头翻译一下英语句子吗?谢谢了啊.

来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/07/18 01:04:41
英语高手大侠们,能再给小馒头翻译一下英语句子吗?谢谢了啊.
翻译成中文,材料学有关的论文..难啊..跪谢了啊 (涉及公式的可以不用翻译成汉语)
Alternative methods to evaluate △Keff were proposed in (44,45). The adjusted compliance ratio (ACR) model (44) is based on the hypothesis of a crack driving force proportional to the strain magnitude. A correction is applied to the applied △K is made on the basis of the ratio of the measured strain range to ideally closure-free one, see Fig.2 △Keff is then obtained as
Fig.2 Method for ACR closure correction evaluation(44) (图我就不给你翻译了啊)
△ Keff = △K * ACR (2)
ACR=Cs-Ci∕Co-Ci (2bis)
Where Ci is the specimen compliance before crack initiation, and Cs and Co are obtained from the load vs. displacement plot for a cracked specimen, see Fig.2. the ACR parameter is independent from the measurement location. Kopen is then obtained as
Kopen = Kmax - △Keff (3)
At very low FCG rates, it is known that the most important closure mechanisms are RICC and OICC, which may cause contact not immediately at the crack tip but someway behind that, Fig. 3a. According to this, a model was proposed in (450 that corresponds to the presence of a layer of thickness 2h inserted between crack faces at a given distance, d, from the crack tip. The evaluation of the crack driving force for this situation leads to
Kmax -2/π Kopen - (1-2/π)Kmin <△Keff < Kmax -2/π Kopen (4)
It can be noticed that △Keff is independent from h and for low R-ratios △Keff ≌ Kmax -(2/π). Kopen. the two models, even though quite different in formulation, rely on the same physical assumption, that is the crack does not always close completely.
评估△Keff的交替法提议(44,45).被调整的服从比率(ACR)模型(44)根据高明的驱动力的假说比例与张力巨大.更正被申请于应用的△K根据被测量的张力范围理想地说被做无关闭一个的比率,看见Fig.2 △Keff然后获得
Fig.2 ACR关闭更正评估的(44)方法
△ Keff = △K * ACR (2)
ACR=Cs-Ci∕Co-Ci (2bis)
Where Ci是标本服从在高明的启蒙之前,并且电缆敷设船和Co从装载获得对一个破裂的标本的位移剧情,看见Fig.2 ACR参量与测量地点是独立的.Kopen然后获得
Kopen = Kmax - △Keff (3)
At非常低FCG对估计,知道最重要的关闭机制是RICC和OICC,也许不立刻导致联络在高明的技巧,但是someway后面那,图3a.根据此,对应于厚度2h层数出现的模型提议(450插入了在高明的面孔之间在特定远处,d,从高明的技巧.高明的驱动力的评估这个情况的导致
Kmax -2/π Kopen - (1-2/π)Kmin <△Keff < Kmax -2/π Kopen (4)
It可以被注意△Keff是独立的与h和为低R比率△Keff ≌ Kmax - (2/π).Kopen.二个模型,即使相当不同在公式化,依靠同一个物理假定,是裂缝不总是紧密完全地.评估△Keff的交替法提议(44,45).被调整的服从比率(ACR)模型(44)根据高明的驱动力的假说比例与张力巨大.更正被申请于应用的△K根据被测量的张力范围理想地说被做无关闭一个的比率,看见Fig.2 △Keff然后获得
Fig.2 ACR关闭更正评估的(44)方法(图我就不给你翻译了啊)
△ Keff = △K * ACR (2)
ACR=Cs-Ci∕Co-Ci (2bis)
Where Ci是标本服从在高明的启蒙之前,并且电缆敷设船和Co从装载获得对一个破裂的标本的位移剧情,看见Fig.2 ACR参量与测量地点是独立的.Kopen然后获得
Kopen = Kmax - △Keff (3)
At非常低FCG对估计,知道最重要的关闭机制是RICC和OICC,也许不立刻导致联络在高明的技巧,但是someway后面那,图3a.根据此,对应于厚度2h层数出现的模型提议(450插入了在高明的面孔之间在特定远处,d,从高明的技巧.高明的驱动力的评估这个情况的导致
Kmax -2/π Kopen - (1-2/π)Kmin <△Keff < Kmax -2/π Kopen (4)
It可以被注意△Keff是独立的与h和为低R比率△Keff ≌ Kmax - (2/π).Kopen.二个模型,即使相当不同在公式化,依靠同一个物理假定,是裂缝不总是紧密完全地.