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(x-6y)/(x²-4y²)+(2y)/(x²-2xy)

来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/11/08 10:55:37
(x-6y)/(x²-4y²)+(2y)/(x²-2xy)
原式=(x-6y)/(x+2y)(x-2y)+2y/x(x-2y)
=(x²-6xy+2xy+4y²)/x(x+2y)(x-2y)
=(x²-4xy+4y²)//x(x+2y)(x-2y)
=(x-2y)²/x(x+2y)(x-2y)
=(x-2y)/(x²+2xy)
(x-6y)/(x²-4y²)+(2y)/(x²-2xy) 已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y² (-x-2y)(x²-2xy+4y²) 化简(x²y-4y²)/(x²+4xy+4y²)*[(4xy)/(x-2y)+x 1.化简求值：(x+y)(x-y)-(x-y)²-6x²y÷2y+(2xy)²÷(-4xy 化简求值(x+y)(x-y)-(x-y)²-6x²y/2y+(2xy)²/(-4xy)其中 化简求值(x+y)(x-y)-(x-y)²-6x²y除2y+(2xy)²除(-4xy)其中 x-y/x²÷x²-2xy+y²/xy*（xy-x²） A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²+3x-y,若x= 设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若x 3x²y+xy²-[2xy²-4x²y+（x²y-2xy²） (2x²y-3xy²)-3(x²y-2xy²)+2（x²y-4xy&#