2x-1/3-10x 1/6=2x-1/4-1过程
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
高数题求解答过程f(x)=x(x-1)(x+2)(x-3)(x+4).(x+100)求f'(1)要过程,答案我有是-10
计算:(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
2x-1\3-10x-1\6=2x+1\4-1要过程
2x-1/3-10x 1/6=2x-1/4-1过程
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
x*(x+1)*(x+2)*(x+3)=360 x=?计算过程以及结果
2/3根号(9x)+6根号(x/4)-2x根号(1/x)..要过程!
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550