log2√5/56+log^14-1/2log2^35 (2lg2+lg3)/(2+lg0.36+2lg2)
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log2√5/56+log^14-1/2log2^35 (2lg2+lg3)/(2+lg0.36+2lg2)
√是根号,5/56全在根号下
√是根号,5/56全在根号下
log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)
=1/2log2 (5/56)-1/2log2 (35)+log2 (14)
=1/2[log2 (5/56/35)]+log2 (14)
=1/2log2 [1/(7^2*8)]+log2 (14)
=1/2(log2 [7^(-2)*2^(-3)]+log2(2*7)
=1/2[-2log2 (7)-3]+log2 (2)+log2 (7)
=-log2 (7)-3/2+1+log2 (7)
=-1/2
=1/2log2 (5/56)-1/2log2 (35)+log2 (14)
=1/2[log2 (5/56/35)]+log2 (14)
=1/2log2 [1/(7^2*8)]+log2 (14)
=1/2(log2 [7^(-2)*2^(-3)]+log2(2*7)
=1/2[-2log2 (7)-3]+log2 (2)+log2 (7)
=-log2 (7)-3/2+1+log2 (7)
=-1/2
log2√5/56+log^14-1/2log2^35 (2lg2+lg3)/(2+lg0.36+2lg2)
1/(1+log3 2)+1/(1+log2 3)=lg3/(lg2+lg3)+lg2/(lg2+lg3)=1解释一下这
2lg2+lg3除以2+lg0.36+2lg2
计算 (2lg2+lg3)/(1+lg0.6+lg2)
lg0.5/lg0.9怎么化为-lg2/2lg3-1,要详细哦,跪求,对数
当lg2=a,lg3=b时求log2^12和lg3/2
当lg2=a,lg3=b求log2^12和lg3/2
求1+1/2lg0.36+1/3lg8分之2lg2+lg3的值
(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)
2lg2+lg3除以1+1/2lg0.36+1/3lg8等于多少?
第一题(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)
计算2lg2+lg3/1+1/2lg0.36+lg8如题