求微积分arctan(x^1/2)dx
求微积分arctan(x^1/2)dx
求积分∫(arctan(1/x)/(1+x^2))dx
微积分求解:∫arctan(x) dx
∫arctan√(x^2-1)dx求不定积分
∫Arctan(1+x^2)dx怎么求?
函数y=arctan(1+x^2)求dy/dx
不定积分arctan(1+x^1/2)dx
求不定积分arctan(x^1/2)/((x^1/2)×(1+x))dx
求不定积分 1/(X^2+1)*arctan[(1+x)/(1-x)]dx
求不定积分arctan(1/x)/(1+x2)dx
∫arctan(1/x) dx 谁知道怎么求?
y=(1+x^2)arctan x 用MATLAB求(d^2*y)/dx^2