（1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/18 16:51:53

（1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2）
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⑴利用换底公式,将所有的式子换成以10为底的对数：
原式=lg27/lg4 × lg8/lg25 × lg5/lg9
=lg3³/lg2² × lg2³/lg5² × lg5/lg3²
=(3lg3)/(2lg2) × (3lg2)/(2lg5) × (lg5/2lg3)
=9/8
⑵由log(a^m) (b^n)=(n/m)loga b
则原式=(log2² 3 + log2³ 3)(log3 2 + log3² 2)
=[(1/2)log2 3 + (1/3)log2 3][log3 2 + (1/2)log3 2]
=[(5/6)log2 3][(3/2)log3 2]
=5/4

（1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2 (log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9） (log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)= 计算（log4 3+ log8 3）（log3 2+ log9 2）-- log1/2 32^(1/3)+5^（log2 【（log4）^3+.（log8）^3】【.（log3）^2+.（log9）^2】=几啊（log3 2）+log9 2)*(log4 3+log8 3)+(log3 3^1/2)^2+ln根号e-lg1 化简(log4(3)+log8(3))(log3(2)+log9(2)) (log4^3+log8^3)(log3^2+log9^2) 求值(log4(3)+log8(3))×(log3(2)+log9(2)) 求值(log3(2)+log9(2))*(log4(3)+log8(3)) (log3 2+log9 2)*(log4 3+log8 3)求值 (log3^2 + log9^4)×(log4^3 + log8^3)