1/3.1/24.1/36.1/49 ( ) a.1/62 b.1/63 c.1/64 d.1/65
1/3.1/24.1/36.1/49 ( ) a.1/62 b.1/63 c.1/64 d.1/65
A B C D × 9 ___________________ D C B A (1) A = ( )(2) B = (
一直a>b>c>d,则(1/(a-b)+1/(b-c)+1/(c-d))*(a-d)的最小值
定义区间(c,d),[c,d),(c,d],[c,d]的长度均为d-c(d>c).已知实数a>b,则满足1/(x-a)+
已知a>b>c>d,求证1/a-b+1/b-c+1/c-a>=9/a-d
a=b=c=1; a+=b*=c%=a+b+c; printf("%d,%d,%d\n",a,b,c) 计算顺序
设a,b,c满足ab+bc+cd+da=1,求证:a^3/(b+c+d)+b^3/(a+c+d)+c^3/(a+b+d)
#include main() { int a,b,c; scanf("%d,%d",&a,&b); if(a>b+1)
已知a、b、c、d满足方程组3a+b+c+d=1a+3b+c+d=9a+b+3c+d=9a+b+c+3d=5
已知实数a,b,c,d满足下列条件 1、d>c2、a+b=c=3、a+d
如果a分之b*c分之d=1,并且a分之b是最简真分数,那么().A.c=d B.c<d C.c>d D无法确定c,d的大
1/3,1/24,1/36,1/49,( )A.1/62 B.1/63 C.1/64 D.1/64