若z的共轭复数为z f(z+i)=z+2i则 f(3+2i)=
若z的共轭复数为z f(z+i)=z+2i则 f(3+2i)=
:若f((z+1)的共轭)=2z+z的共轭+i,则f(i)等于( )
f(z)=2z+z的共轭-3i,f(z的共轭+i)=6-3i,试求f(-z)
复数z的共轭复数为-z,已知z=2i/1-i,则z×-z=?
复数z满足(z-3)(2-i)=5(i为虚数单位),则z的共轭复数为(
Z+|Z的共轭复数|=2+i .Z=?
已知复数z=2i1+i,则z的共轭复数.z是( )
复数z满足(z-3)(2-i)=5(i为虚数单位),则z的共轭复数.z为( )
已知复数z=a-根号下3i,若z^2=z的共轭,则实数a为
f(z)=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?
f(z共轭复数)=z+5i,则f(3+i)=
已知f(共轭复数+i)=z+2共轭复数+2i 则f(3+2i)等于多少啊