计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/10/04 16:15:53
计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1
:(3a^n+2+6a^n+1-9a^n)÷3a^n-1
=3a^n+2÷3a^n-1+6a^n+1÷3a^n-1-9a^n ÷3a^n-1
=a³+2a²-3a
再问: (3a^(n+2)+6a^(n+1)-9^(n))÷3a^(n-1)
再答: �����ľ������������һ��a (3a^(n+2)+6a^(n+1)-9 a ^(n))��3a^(n-1) =3a^(n+2)��3a^(n-1)+6a^(n+1)��3a^(n-1)-9a^n ��3a^(n-1) =a³+2a²-3a
=3a^n+2÷3a^n-1+6a^n+1÷3a^n-1-9a^n ÷3a^n-1
=a³+2a²-3a
再问: (3a^(n+2)+6a^(n+1)-9^(n))÷3a^(n-1)
再答: �����ľ������������һ��a (3a^(n+2)+6a^(n+1)-9 a ^(n))��3a^(n-1) =3a^(n+2)��3a^(n-1)+6a^(n+1)��3a^(n-1)-9a^n ��3a^(n-1) =a³+2a²-3a
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