已知弧长122.,8,求弦长!
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已知弧长122.,8,求弦长!
cos(180×61/πR)=R-1.8/R
cos(180×61/πR)=R-1.8/R
已知弧长C=122.,弧高H=1.8,求弦长L?
弧的半径为R,弧所对的圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=1000
R1=1031.231
R2=1033.303
R3=1033.311
R4=1033.311
弧的半径R=1033.311
A=C/R
=122/1033.311
=0.11807弧度
=0.11807*180/PI
=6.765度
L=2*R*SIN(A/2)
=2*1033.311*SIN(6.765/2)
=121.93
弧的半径为R,弧所对的圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=1000
R1=1031.231
R2=1033.303
R3=1033.311
R4=1033.311
弧的半径R=1033.311
A=C/R
=122/1033.311
=0.11807弧度
=0.11807*180/PI
=6.765度
L=2*R*SIN(A/2)
=2*1033.311*SIN(6.765/2)
=121.93