mn(1/m-1/n)÷m^2-n^2/m+n
先化简(m/m-n-n/m+n+2mn/m²-n²)²÷m²+mn/m,若m=1
mn(1/m-1/n)÷m^2-n^2/m+n
1+n-m÷m²-n² --- ---- m+2n m²+4mn+4n²
1+n-m/m+2n÷m²-n²/m²+4mn+4n²=
m(m+n)(m-n)-m(m+n)的平方,其中m+n=1,mn=-1/2
数学题[(m+3n)(m-3n)+(2n-m^2)+5n^2(1-m)-(2m^2-m^2n)÷(-1/2mn)
化简(m²/m-n - m+n)÷2m²-mn/n - m
化简:(-n/m)÷n/m^2-m的结果是( )A.-m-1 B.-m+1 C.-mn+m D.-mn-n
(1)(m^2+n^2/m-n) +2mn/n-m
化简求值(m+n)(m^2-mn+n^2)+(m-n)(m^2+mn+n^2)m=-1 n=199
因式分解(mn+m)2-(n+1)2
已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值