集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0

集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0 集合A=｛(x,y)|x^2+mx-y+2=0｝,集合｛(x,y)|x-y+1=0,且0 集合A=｛(x,y)丨x^2+mx-y+2=0} 集合B=｛（x,y)丨x-y+1=0 且0≤x≤2｝ 又 A∩B≠空集 集合A={（x,y) x^2+mx-y+2=0},集合B={(x,y) x-y+1=0且0≤x≤2},又A交B不等于空集 已知集合A={（x,y)|x*x+mx-y+2=0},B={(x,y)|x-y+1=o,0 1.集合A={(x,y)｜x∧2+mx-y+2=0},集合B={(x,y)｜x-y+1=0,且0≤X≤2} 集合A={（x,y)|x2（平方）+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0≤x≤2},又A∩B= 设集合A={x|x^2+mx+1=0,x∈R},B=y|y 已知集合A={(x,y)|x^2+mx+2=y},B={(x,y)|x-y+1=0,0 高二数学题难死了集合A={(x,y)丨y=-x^2+mx-1},B={(x,y)丨y=3-x,0 已知集合A={(x,y)|y=-x^2+mx-1},B={(x,y)|x+y=3,0≤x≤3}.且A∩B是单元素集,求实 已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y .,求实数m的取值笵围.