作业帮会几道就写几道就行了‘
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/11/09 02:43:28
会几道就写几道就行了‘
*是乘号、^是次方,我这样表示哦,看不懂问哦
1、1/(2c^2*d)+1/(3c*d^2)=3d/(6c^2*d^2)+2c/(6c^2*d^2)=(3d+2c)/(6c^2*d^2)
2、3/(2m-n)-(2m-n)/(2m-n)^2=3/(2m-n)-1/(2m-n)=2/(2m-n)
3、a/(a^2+b^2)-1/(a+b)=a/(a+b)(a-b)-(a-b)/(a+b)(a-b)=(a-a+b)/(a+b)(a-b)=b/(a+b)(a-b)
4、a^2/(a-1)-a-1=a^2/(a-1)-(a^2-a)/(a-1)-(a-1)/(a-1)=[a^2-(a^2-a)-(a-1)]/(a-1)=1/(a-1)
1、1/(2c^2*d)+1/(3c*d^2)=3d/(6c^2*d^2)+2c/(6c^2*d^2)=(3d+2c)/(6c^2*d^2)
2、3/(2m-n)-(2m-n)/(2m-n)^2=3/(2m-n)-1/(2m-n)=2/(2m-n)
3、a/(a^2+b^2)-1/(a+b)=a/(a+b)(a-b)-(a-b)/(a+b)(a-b)=(a-a+b)/(a+b)(a-b)=b/(a+b)(a-b)
4、a^2/(a-1)-a-1=a^2/(a-1)-(a^2-a)/(a-1)-(a-1)/(a-1)=[a^2-(a^2-a)-(a-1)]/(a-1)=1/(a-1)