|x|+|y|

{(x,y) |x|+|y| x>y?x:y (x+y) X、Y 1.(x-y)(x+y)+(x-y)+(x+y) |x|+|y| x y x+yy x+y xx+y x y 1、x(x-y)(x+y)-x(x+y)^2 z/(x-y) × y/(x+y) # define ABS_MOD(x,y) (((x) < 0) ((((x) % (y)) + (y)) % (y)) x(x-y)+4(y-x)因式分解 #define max(x,y) x>y?x: