1+2+3+4+123+1+2+3+4+123=
1+2+3+4+123+1+2+3+4+123=
123+123+1+2+3
s={1,2,3,4,5,6,7,8},G={(1),(123)(456),(132)(456),(78),(123)(
123除以123 123/332+2/333+4/333+6/333+8/333+.332/333-(1/333+3/3
123*3/2-246*1/4 简便计算
简便计算123除以123又123/332+(2/333+4/333*.+332/333) (1/333+.+331/3
1=5 2=25 3=123 4=625 5=?
1=123 2=432 3=125 4=512 5=?
1=5,2=135,3=123,4=134,5=?
(-123)+3又3分之1+(-4又4分之1)+123=
MATLAB中使矩阵a=[123;456]变成a=[1 2 3;4 5
(1/2)123÷123又123/332+(2/333+4/333+6/333+…332/333)-(1/333+3/3