y=x/(√a²-x²),求dy/dx!

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/18 21:15:49

dy/dx=[x/√(a²-x²)]'
=[√(a²-x²)+x²/√(a²-x²)]/(a²-x²)
=[(a²-x²)+x²]/(a²-x²)^(3/2)
=a²/(a²-x²)^(3/2).

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