(1-1/2²)(1-1/3²)(1-1/4²)(1-1/5²)……(1-1/2
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/10/06 07:06:39
(1-1/2²)(1-1/3²)(1-1/4²)(1-1/5²)……(1-1/2007²)(1-1/2008²)
要过程!
要过程!
/> (1-1/2²)(1-1/3²)(1-1/4²)(1-1/5²)……(1-1/2007²)(1-1/2008²)
=(1+1/2)(1-1/2)(1+1/3)(1-1/3)……(1+1/2007)(1-1/2007)(1+1/2008)(1-1/2008)
=(1+1/2)(1+1/3)……(1+1/2008)*(1-1/2)(1-1/3)(1-1/2008)
=3/2*4/3*5/4*……*2009/2008*1/2*2/3*3/4*……*2007/2008
=2009/2*1/2008
=2009/4016
=(1+1/2)(1-1/2)(1+1/3)(1-1/3)……(1+1/2007)(1-1/2007)(1+1/2008)(1-1/2008)
=(1+1/2)(1+1/3)……(1+1/2008)*(1-1/2)(1-1/3)(1-1/2008)
=3/2*4/3*5/4*……*2009/2008*1/2*2/3*3/4*……*2007/2008
=2009/2*1/2008
=2009/4016
(1-1/2²)(1-1/3²)(1-1/4²)……(1-1/10²)
(1-1/2²)(1-1/3²)(1-1/4²)……*(1-1/2008²)
求和:1²-2²+3²-4²+5²-6²+…+99²
初二数学题(1-1/2²)(1-1/3²)(1-1/4²)…(1-1/9²)(1
(1²+3²+5²+……+99²)-(2²+4²+6
求值(2²+4²+6²+……+2000²)-(1²+3²+5
(1-1/2²)(1-1/3²)(1-1/4²)(1-1/5²)……(1-1/2
计算1-2²+3²-4²+5²-6²+…+99²-100
因式分解[1-1/2²][1-1/3²】……【1-1/10²】
数列2²+1/2²-1,3²+1/3²-1……(n+1)²+1/(n-
1-2²+3²-4²+5²-6²+……+99²-100
(1-1/2²)(1-1/3²)(1-1/4²)……(1-1/9²)(1-1/1