若多项式x²-2xy+y²-x+y-1=0,求x-y的值.
若多项式x²-2xy+y²-x+y-1=0,求x-y的值.
求多项式2x²-3xy+y²-2xy-2x²+5xy-2y+1的值,其中x=22/7,y=
若x² +xy+y² =14,x² -xy+y²=28求x+y的值
若x²+xy+y²=14,x²-xy+y²=28,求x+y的值
已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值
已知X²-5XY+6Y²=0,求(X²+3XY)\2Y²的值
若x-2y=0,求代数式-x²+xy+y²分之2x²-xy-y²的值.
1.若x+y=3,xy=1,求(x-y)²,x²+y²的值.
x²+y²+4x-8y+20=0,求分式x²-y²/xy的值
|x+2y+3|+(2x+y)²=0求x²-xy+y²
若x²+y²-2x-6y+10=0,求分式x²-y²/xy的值?
已知x/y=3,求x²+2xy-3y²/x²-xy+y³的值