{int a1=3,a2=9;printf("%d\n",(a1,a2));} 与{int a1=3,a2=9;prin
{int a1=3,a2=9;printf("%d\n",(a1,a2));} 与{int a1=3,a2=9;prin
main() { int a1,a2,x; a1=100; a2=50; x=a1-a2; printf("x=%d\n
main() { int a1,a2,x; a1=10;a2=20;x=a1*a2; printf("a1=%d,a2+
void fun(char *a1,char *a2,int n) { int k; for(k=0; k
char a1='M',a2='m';为什么printf("%c\n",(a1,a2))是m?
char a1='M',a2='m'; printf("%c\n",a1,a2);结果?
三个正整数a1,a2,a3,且a1+a2+a3=a1×a2×a3,a1≥1,a2≥2,a3≥3,求a1,a2,)
#include void main(void) {int a1=10,a2=3; float a3=8.0; cout
#define F(m,n) m*n main() { int x=5,y=3,a1,a2; a1=F(x+y,x-y)
main( ) {unsigned int a=3,b=10; printf("%d/n",a1); }
计算数学表达式 的值#include int main(){ int a1=m,a2=n,a3=m-n; double
设a1,a2,a3为正数,求证a1*a2/a3+a2*a3/a1+a3*a1/a2>=a1+a2+a3