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已知f(阿尔法)=sin(π/2+α)+3sin(-π-α)/2cos(11π/2-α)-cos(5π-α).

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/11/09 00:57:24
已知f(阿尔法)=sin(π/2+α)+3sin(-π-α)/2cos(11π/2-α)-cos(5π-α).
(1)化简f(α) (2)已知tanα=3,求f(α)的值
1,f(α)=sin(π/2+α)+3sin(-π-α)/2cos(11π/2-α)-cos(5π-α).
=(cosα-3sinα)/(-2sinα+cosα)
f(α)=(cosα-3sinα)/(cosα-2sinα)
2,tanα=3
f(α)=(cosα-3sinα)/(cosα-2sinα)
=(1-3tanα)/(1-2tanα)
=(1-9)/(1-6)
=8/5