请问这样的方程组在如何用matlab求解呀?
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/19 10:31:09
请问这样的方程组在如何用matlab求解呀?
[x,y]=solve('(0.14*0.825+x-y)(y+3*x)^3/[(0.4125-0.14*0.825-x)*(0.28*0.825+0.4125-x-y)*(0.4125+0.4125+1.07*0.825+2*x)^2]=9.23','y(y+3*x)/[(0.14*0.825+x-y)*(0.825*0.28+0.4125-x-y)]=1.54')
我弄到matlab中显示的是
Warning:Explicit solution could not be found.
> In solve at 81
x =
[ empty sym ]
y =
[]
是不是该用fsolve呀,应该怎么弄呢?
![](http://img.wesiedu.com/upload/f/82/f825e0c8176cd821e9e009b5ea35a134.jpg)
[x,y]=solve('(0.14*0.825+x-y)(y+3*x)^3/[(0.4125-0.14*0.825-x)*(0.28*0.825+0.4125-x-y)*(0.4125+0.4125+1.07*0.825+2*x)^2]=9.23','y(y+3*x)/[(0.14*0.825+x-y)*(0.825*0.28+0.4125-x-y)]=1.54')
我弄到matlab中显示的是
Warning:Explicit solution could not be found.
> In solve at 81
x =
[ empty sym ]
y =
[]
是不是该用fsolve呀,应该怎么弄呢?
![](http://img.wesiedu.com/upload/f/82/f825e0c8176cd821e9e009b5ea35a134.jpg)
你输入有误:
1.少了两个乘号“*”
2.把[ ]改成()
正确输入如下:
[x,y]=solve('(0.14*0.825+x-y)*(y+3*x)^3/((0.4125-0.14*0.825-x)*(0.28*0.825+0.4125-x-y)*(0.4125+0.4125+1.07*0.825+2*x)^2)=9.23','y*(y+3*x)/((0.14*0.825+x-y)*(0.825*0.28+0.4125-x-y))=1.54')
1.少了两个乘号“*”
2.把[ ]改成()
正确输入如下:
[x,y]=solve('(0.14*0.825+x-y)*(y+3*x)^3/((0.4125-0.14*0.825-x)*(0.28*0.825+0.4125-x-y)*(0.4125+0.4125+1.07*0.825+2*x)^2)=9.23','y*(y+3*x)/((0.14*0.825+x-y)*(0.825*0.28+0.4125-x-y))=1.54')