x=θ(1-sinθ) y=θcosθ 求dy/dx

x=θ(1-sinθ) y=θcosθ 求dy/dx cos(x+y)+y=1 求dy/dx d{cos(x-y)=sin(x-y)(dx-dy)这里dx-dy是什么意思呢? 求 sin y/cos y dy=sin x/cos x dx 两边同时积分的计算过程 设x=e'sin t,y=e'cos t,求dy/dx. 求导：x=cos^4*t,y=sin^4*t,求dy/dx 设函数y=sin(1+x),则dy=cos(1+x)dx 对么 y=sin(x+y) 求dy/dx y= (cos x)^x,求dy/dx 对于x=cos(y/x),求dy/dx. x=sin(y/x)+e^2 求dy/dx x=2sin(t),y=cos(t+pie),求dy/dx,和d^2y/dx^2,在点（0,-1）