因式分解:(x+y-2xy)(x+y-2)+(1-xy)2=______.
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因式分解:(x+y-2xy)(x+y-2)+(1-xy)2=______.
(x+y-2xy)(x+y-2)+(1-xy)2
=(x+y)2-2(1+xy)(x+y)+4xy+1-2xy+x2y2
=(x+y)2-2(1+xy)(x+y)+(1+xy)2
=(x+y)2-(1+xy)(x+y)-(1+xy)(x+y)+(1+xy)2
=(x+y)(x+y-1-xy)-(1+xy)(x+y-1-xy)
=(x+y-1-xy)(x+y-1-xy)
=(x+y-1-xy)2 .
故答案为:(x+y-1-xy)2 .
=(x+y)2-2(1+xy)(x+y)+4xy+1-2xy+x2y2
=(x+y)2-2(1+xy)(x+y)+(1+xy)2
=(x+y)2-(1+xy)(x+y)-(1+xy)(x+y)+(1+xy)2
=(x+y)(x+y-1-xy)-(1+xy)(x+y-1-xy)
=(x+y-1-xy)(x+y-1-xy)
=(x+y-1-xy)2 .
故答案为:(x+y-1-xy)2 .
因式分解:(x+y)(x+y+2xy)+(xy+1)(xy-1)=______.
因式分解:(x+y-2xy)(x+y-2)+(1-xy)2=______.
因式分解:16(x-y)2-24xy(y-x)=8(x-y)(______).
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