(1/2003-1)(1/2002-1)(1/2011-1)(1/2000)(1/1999-1)…(1/1001-1)(
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/17 01:25:05
(1/2003-1)(1/2002-1)(1/2011-1)(1/2000)(1/1999-1)…(1/1001-1)(1/1000-1)
(1/2003-1)(1/2002-1)(1/2001-1)(1/2000-1)(1/1999-1)……(1/1001-1)(1/1000-1)
=(-2002/2003)×(-2001/2002)×(-2000/2001)×(-1999/2000)×(-1998/1999)×……×(-1000/1001)×(-999/1000)
=999/2003
一共有2003-999=1004个负分数相乘,积为正数,约分后剩下第一个因数的分母2003和最后一个因数的分子999
=(-2002/2003)×(-2001/2002)×(-2000/2001)×(-1999/2000)×(-1998/1999)×……×(-1000/1001)×(-999/1000)
=999/2003
一共有2003-999=1004个负分数相乘,积为正数,约分后剩下第一个因数的分母2003和最后一个因数的分子999
(1/2003-1)(1/2002-1)(1/2011-1)(1/2000)(1/1999-1)…(1/1001-1)(
求:(1/2003-1)(1/2002-1)(1/2001-1)(1/2000-1)(1/1999-1)…(1/1001
1999*1998/1+1999*2000/1+2000*2001/1+2001*2002/1+2002*2003/1+
1/1999×2000+1/2000×2001+1/2001×2002+1/2002×2003+1/2003×2004+
(2003/1-1)(2002/1-1)(2001/1-1)(2000/1-1)(1999/1-1)...(1001/1
(1/2004 -1)(1/2003 -1)(1/2002 -1).(1/1001 -1)(1/1000 -1)
(1/2003-1)(1/2002-1)(1/2001-1)...*(1/1001-1)(1/1000-1)
求(1/2003-1)X(1/2002-1)X(1/2001-1)X(1/2000-1)X1/1999-1)...(1/
(1+1/1999+1/2000+1/2001)×(1/1999+1/2000+1/2001+1/2002)
(1+1/1999+1/2000)*(1/1999+1/2000+1/2001+1/2002)-(1+1/1999+1/
写过程(1/2004-1) (1/2003-1) (1/2002-1)...(1/1001-1) (1/1000-1)=
(2003/1-1)×(2002/1-1)×(2001/1-1)×.×(1001/1-1)×(1000/1-1)=?