四平方加x分之七加x平方减x分之一等于x平方减一分之六-搜答案-智慧作业帮

x²-x-1=0,所以x²=x+1,x^4=（x+1）²=x²+2x+1=x+1+2x+1=3x+2,x^5=（3x+2）x=3x²+2x=3（x+1

由题意可得：x+1/x-1=7(x+1/x)^2=64所以x^2+1/x^2=62所以(x^4+x^2+1)/x^2=x^2+1+1/x^2=63再问：我看不懂，您能解释详细点吗？谢谢了再答：（x^2

有歧义啊啊!再问：？再答：你这说的太不清楚了，建议写下来拍照再问：再问：再问：再答：第一个是x+1/x+2再答：第二个是1/a+2再答：第三个太麻烦再问：再问：对不对？再答：对再答：分呢！

请楼主描述清楚一些

(x的平方加x加1)分之x等于a∴(x²+x+1)/x=1/ax+1+1/x=1/ax+1/x=1/a-1=(1-a)/a两边平方得x²+2+1/x²=(1-a)

3/(x+1)

x^2-5x+1=0方程两边同除以xx-5+1/x=0x+1/x=5(x^4+1)/x^2=x^2+1/x^2=(x+1/x)^2-2=5^2-2=25-2=23

∵x^2-3x+1=0显然x不等于0∴x-3+1/x=0∴x+1/x=3∴x^2+1/x^2+2=9∴x^2+1/x^2=7∴原式=1/(x^2+1+1/x^2)=1/(7+1)=1/8

题意是这样的吧：求(x²+9x)/(x²+3x)+(x²-9)/(x²+6x+9)原式=(x²+9x)/(x²+3x)+(x+3)(x-3)

解题思路：利用降次，整体代换的方法，由已知条件变换的思路来解。解题过程：

再问：详解

你还是把式子写出来吧,你这句话有歧义啊再问：不知道怎么写啊。。。再答：这个就不好弄了，呵呵。。。

先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+

原式=x(x-9)/x(x+3)-(x+3)(x-3)/(x-3)²=(x-9)/(x+3)-(x+3)/(x-3)=(x²-12x+27-x²-6x-9)/(x+3)(

/>∵x/(x²-x+1)=1/6∴(x²-x+1)/x=6x²-x+1=6xx²+1=7x∵(x²+1)×1/x=7x×1/xx²×1/x

x+1/x=4得x^2+2+1/x^2=16x^2+1/x^2=14x四次方加x平方加1分之x平方=x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/15

1/(x+1)+1/(x-1)=7/(x^2-1)(x-1)/[(x+1)(x-1)]+(x+1)/[(x+1)(x-1)]=7/(x^2-1)(x-1)/(x^2-1)+(x+1)/(x^2-1)=

x/(x^2-x+1)=7,(x^2-x+1)/x=1/7x+(1/x)-1=1/7x+(1/x)=8/7x^2/(x^4+x^2+1)=1/[(x^4+x^2+1)/x^2]=1/[x^2+(1/x

x^4+x^3+(9/4)x^2+x+1=x^4+(1/2)x^3+x^2+(1/2)x^3+(1/4)x^2+(1/2)x+x^2+(1/2)x+1=x^2(x^2+(1/2)x+1)+(1/2)x